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3m^2-13=-8-24m-2m^2
We move all terms to the left:
3m^2-13-(-8-24m-2m^2)=0
We get rid of parentheses
3m^2+2m^2+24m+8-13=0
We add all the numbers together, and all the variables
5m^2+24m-5=0
a = 5; b = 24; c = -5;
Δ = b2-4ac
Δ = 242-4·5·(-5)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-26}{2*5}=\frac{-50}{10} =-5 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+26}{2*5}=\frac{2}{10} =1/5 $
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